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Q. No.Find the number of significant figures in the value 0.00340.
1. five (5)
2. Two (2)
3. Four (4)
4. Three (3)
Subtopic: Introduction |
78%
Level 2: 60%+
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If the density of \(NaOH\) solution is \(1.2~\text{g cm}^{-3}\), find the molality of this solution: (Round off to the nearest integer)
[Given: Atomic masses:
\(Na:23.0~u;~~O:16.0~u;~~H:1.0~u\)]
[Density of \(H_2O:1.0~\text{g cm}^{-3}\) ]
1. 12 m
2. 18 m
3. 5 m
4. 3 m
[Given: Atomic masses:
\(Na:23.0~u;~~O:16.0~u;~~H:1.0~u\)]
[Density of \(H_2O:1.0~\text{g cm}^{-3}\) ]
1. 12 m
2. 18 m
3. 5 m
4. 3 m
Subtopic: Concentration Based Problem |
Level 3: 35%-60%
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The complete combustion of butane (\(C_4H_{10}\)) in the presence of excess oxygen produces carbon dioxide and water. If \(72.0 \text{ g} \) of water is produced during the process, the mass of butane utilized is \(x \times 10^{-1} \text{ g}\):
Find the value of x to the nearest integer:
1. 4642. 345
3. 671
4. 124
Subtopic: Equation Based Problem |
81%
Level 1: 80%+
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NaClO3 is used, even in spacecraft, to produce O2 . The daily consumption of pure O2 by a person is 492 L at 1 atm, 300 K. How much NaClO3 , in grams, is required to produce O2 for the daily consumption of a person at 1 atm, 300 K?
\(\begin{aligned} & \mathrm{NaClO}_3(\mathrm{~s})+\mathrm{Fe}(\mathrm{s}) \rightarrow \mathrm{O}_2(\mathrm{~g})+\mathrm{NaCl}(\mathrm{s})+\mathrm{FeO}(\mathrm{s}) \\ & \mathrm{R}=0.082 \mathrm{~L} \text { atm } \mathrm{mol}^{-1} \mathrm{~K}^{-1} \end{aligned}\)
1. 2130 gm
2. 106.5 gm
3. 4123 gm
4. 2912 gm
\(\begin{aligned} & \mathrm{NaClO}_3(\mathrm{~s})+\mathrm{Fe}(\mathrm{s}) \rightarrow \mathrm{O}_2(\mathrm{~g})+\mathrm{NaCl}(\mathrm{s})+\mathrm{FeO}(\mathrm{s}) \\ & \mathrm{R}=0.082 \mathrm{~L} \text { atm } \mathrm{mol}^{-1} \mathrm{~K}^{-1} \end{aligned}\)
1. 2130 gm
2. 106.5 gm
3. 4123 gm
4. 2912 gm
Subtopic: Millimole/Equivalent Concept |
75%
Level 2: 60%+
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When \(35 ~mL\) of \(0.15~ M\) lead nitrate solution is mixed with \(20 ~mL\) of \(0.12 ~M\) chromic sulphate solution, \(x× 10^{–5}\) moles of lead sulfate precipitate out. Calculate the value of \(x\). (Round off to the Nearest Integer)
| 1. | 525 | 2. | 124 |
| 3. | 734 | 4. | 223 |
Subtopic: Limiting Reagent |
56%
Level 3: 35%-60%
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If the number of chlorine atoms in \(20~\text{mL}\) of chlorine gas at STP is \(x \times10^{21},\) find the value of \(x\):
[Note: Assume chlorine is an ideal gas at STP]
[Given: \(\mathrm{R = 0.083~ L~ bar~ mol^{–1} ~ K^{–1} , N_A = 6.023 × 10^{23}]}\)
1. 1.0755
2. 2.3456
3. 6.0223
4. 3.1034
[Note: Assume chlorine is an ideal gas at STP]
[Given: \(\mathrm{R = 0.083~ L~ bar~ mol^{–1} ~ K^{–1} , N_A = 6.023 × 10^{23}]}\)
1. 1.0755
2. 2.3456
3. 6.0223
4. 3.1034
Subtopic: Millimole/Equivalent Concept |
62%
Level 2: 60%+
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The mole fraction of a solute in a \(100\) molal aqueous solution is \(\text{x}\) \(× 10^{–2} .\) Find the value of \(\text{x}\).
[Given : Atomic mass : \(H : 1.0 ~u, O : 16.0 ~u\)]
1. 15.8
2. 64.3
3. 34.8
4. 83.1
[Given : Atomic mass : \(H : 1.0 ~u, O : 16.0 ~u\)]
1. 15.8
2. 64.3
3. 34.8
4. 83.1
Subtopic: Concentration Based Problem |
77%
Level 2: 60%+
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If 4 g equimolar mixture of \(\text{NaOH}\) and \(\mathrm{Na_2CO_3}\) contains x g of \(\text{NaOH}\) and y g of \(\mathrm{Na_2CO_3}\), then find the value of x in grams:
1. 2.562
2. 9.354
3. 1.096
4. 3.096
1. 2.562
2. 9.354
3. 1.096
4. 3.096
Subtopic: Concentration Based Problem |
72%
Level 2: 60%+
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The concentration of glucose (\((C_6H_{12}O_6)\) in blood is 0.72 \(gL^{-1}\). If its molarity is expressed in the form \(x \times 10^{-3}\) then calculate the value of \(x\):
[Given: Atomic masses: C = 12, H = 1, O = 16 u]
1. Four (4)
2. Six (6)
3. Two (2)
4. Eight (8)
[Given: Atomic masses: C = 12, H = 1, O = 16 u]
1. Four (4)
2. Six (6)
3. Two (2)
4. Eight (8)
Subtopic: Concentration Based Problem |
84%
Level 1: 80%+
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Methylation of 10 g of benzene gave 9.2 g of toluene. The percentage yield of toluene (to the nearest integer) is:
1. 52%
2. 78%
3. 23%
4. 43%
1. 52%
2. 78%
3. 23%
4. 43%
Subtopic: Concentration Based Problem |
75%
Level 2: 60%+
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