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Q. No.Ferrous sulphate heptahydrate is used to fortify foods with iron. The amount (in grams) of the salt required to achieve 10 ppm of iron in 100 kg of wheat is:
(Atomic weight :Fe = 55.85; S 32.00; O ; 16.00)
1. 3 gram
2. 12 gram
3. 1 gram
4. 4.97 gram
Subtopic: Introduction |
Level 4: Below 35%
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The number of atoms present in 8 g of sodium is expressed as x × 10²³. Calculate the value of x.
Given:
Nₐ = 6.02 × 10²³ mol⁻¹
Atomic mass of Na = 23 u
2. 5.03
3. 8.46
4. 3.50
Subtopic: Moles, Atoms & Electrons |
84%
Level 1: 80%+
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250 mL of \(0.5~\text{M NaOH}\) was added to 500 mL of 1 M HCl. The number of unreacted HCl molecules in the solution after complete reaction is
\(x\times10^{21}.\) Find the value of x (Nearest integer).
\(\left(\mathrm{N}_{\mathrm{A}}=6.022 \times 10^{23}\right)\)
1. 256
2. 465
3. 226
4. 145
\(x\times10^{21}.\) Find the value of x (Nearest integer).
\(\left(\mathrm{N}_{\mathrm{A}}=6.022 \times 10^{23}\right)\)
1. 256
2. 465
3. 226
4. 145
Subtopic: Limiting Reagent |
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Level 2: 60%+
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Methylation of 10 g of benzene gave 9.2 g of toluene. The percentage yield of toluene (to the nearest integer) is:
1. 52%
2. 78%
3. 23%
4. 43%
1. 52%
2. 78%
3. 23%
4. 43%
Subtopic: Concentration Based Problem |
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Level 2: 60%+
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The concentration of glucose (\((C_6H_{12}O_6)\) in blood is 0.72 \(gL^{-1}\). If its molarity is expressed in the form \(x \times 10^{-3}\) then calculate the value of \(x\):
[Given: Atomic masses: C = 12, H = 1, O = 16 u]
1. Four (4)
2. Six (6)
3. Two (2)
4. Eight (8)
[Given: Atomic masses: C = 12, H = 1, O = 16 u]
1. Four (4)
2. Six (6)
3. Two (2)
4. Eight (8)
Subtopic: Concentration Based Problem |
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Level 1: 80%+
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If 4 g equimolar mixture of \(\text{NaOH}\) and \(\mathrm{Na_2CO_3}\) contains x g of \(\text{NaOH}\) and y g of \(\mathrm{Na_2CO_3}\), then find the value of x in grams:
1. 2.562
2. 9.354
3. 1.096
4. 3.096
1. 2.562
2. 9.354
3. 1.096
4. 3.096
Subtopic: Concentration Based Problem |
72%
Level 2: 60%+
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Find the number of significant figures in the value 0.00340.
1. five (5)
2. Two (2)
3. Four (4)
4. Three (3)
1. five (5)
2. Two (2)
3. Four (4)
4. Three (3)
Subtopic: Introduction |
79%
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If the density of \(NaOH\) solution is \(1.2~\text{g cm}^{-3}\), find the molality of this solution: (Round off to the nearest integer)
[Given: Atomic masses:
\(Na:23.0~u;~~O:16.0~u;~~H:1.0~u\)]
[Density of \(H_2O:1.0~\text{g cm}^{-3}\) ]
1. 12 m
2. 18 m
3. 5 m
4. 3 m
[Given: Atomic masses:
\(Na:23.0~u;~~O:16.0~u;~~H:1.0~u\)]
[Density of \(H_2O:1.0~\text{g cm}^{-3}\) ]
1. 12 m
2. 18 m
3. 5 m
4. 3 m
Subtopic: Concentration Based Problem |
Level 3: 35%-60%
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The complete combustion of butane (\(C_4H_{10}\)) in the presence of excess oxygen produces carbon dioxide and water. If \(72.0 \text{ g} \) of water is produced during the process, the mass of butane utilized is \(x \times 10^{-1} \text{ g}\):
Find the value of x to the nearest integer:
1. 4642. 345
3. 671
4. 124
Subtopic: Equation Based Problem |
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Level 1: 80%+
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NaClO3 is used, even in spacecraft, to produce O2 . The daily consumption of pure O2 by a person is 492 L at 1 atm, 300 K. How much NaClO3 , in grams, is required to produce O2 for the daily consumption of a person at 1 atm, 300 K?
\(\begin{aligned} & \mathrm{NaClO}_3(\mathrm{~s})+\mathrm{Fe}(\mathrm{s}) \rightarrow \mathrm{O}_2(\mathrm{~g})+\mathrm{NaCl}(\mathrm{s})+\mathrm{FeO}(\mathrm{s}) \\ & \mathrm{R}=0.082 \mathrm{~L} \text { atm } \mathrm{mol}^{-1} \mathrm{~K}^{-1} \end{aligned}\)
1. 2130 gm
2. 106.5 gm
3. 4123 gm
4. 2912 gm
\(\begin{aligned} & \mathrm{NaClO}_3(\mathrm{~s})+\mathrm{Fe}(\mathrm{s}) \rightarrow \mathrm{O}_2(\mathrm{~g})+\mathrm{NaCl}(\mathrm{s})+\mathrm{FeO}(\mathrm{s}) \\ & \mathrm{R}=0.082 \mathrm{~L} \text { atm } \mathrm{mol}^{-1} \mathrm{~K}^{-1} \end{aligned}\)
1. 2130 gm
2. 106.5 gm
3. 4123 gm
4. 2912 gm
Subtopic: Millimole/Equivalent Concept |
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