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Q. No.The maximum number of atoms is present in which of the following -
1.
1 g of Mg(s)
2.
1 g of O2 (g)
3.
1 g of Li(s)
4.
1 g of Ag(s)
Subtopic: Moles, Atoms & Electrons |
79%
Level 2: 60%+
NEET - 2020
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One mole of carbon atom weights 12 g, the number of atoms in it is equal to:
(Mass of carbon – 12 is )
1.
2.
3.
4.
Subtopic: Moles, Atoms & Electrons |
80%
Level 1: 80%+
NEET - 2020
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The density of a 2 M aqueous solution of NaOH is 1.28 g/. The molality of the solution is:
[molecular mass of NaOH = 40 g mol-1]
| 1. | 1.20 m | 2. | 1.56 m |
| 3. | 1.67 m | 4. | 1.32 m |
Subtopic: Concentration Based Problem |
73%
Level 2: 60%+
NEET - 2019
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An organic compound contains 80 % (by wt.) carbon and the remaining percentage of hydrogen. The empirical formula of this compound is:
[Atomic wt. of C is 12, H is 1]
1. CH3
2. CH4
3. CH
4. CH2
Subtopic: Empirical & Molecular Formula |
75%
Level 2: 60%+
NEET - 2021
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To produce 20 moles of ammonia via Haber's process, how many moles of hydrogen molecules are required?
| 1. | 40 mol | 2. | 10 mol |
| 3. | 20 mol | 4. | 30 mol |
Subtopic: Limiting Reagent | Equation Based Problem |
81%
Level 1: 80%+
NEET - 2019
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Calculate the mass of 95% pure CaCO3 that will be required to neutralize 50 mL of 0.5 M HCl solution according to the following reaction.
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l)
[Calculate up to the second place of decimal point]
CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + 2H2O(l)
[Calculate up to the second place of decimal point]
| 1. | 9.50 g | 2. | 1.25 g |
| 3. | 1.32 g | 4. | 3.65 g |
Subtopic: Equation Based Problem |
55%
Level 3: 35%-60%
NEET - 2022
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Match List-I with List-II:
| List-I (Quantities) |
List-II (Corresponding Values) |
||
| (a) | 4.48 litres of O2 at STP | (i) | 0.2 mole |
| (b) | 12.022 × 1022 molecules of H2O | (ii) | 12.044 × 1023 molecules |
| (c) | 96 g of O2 | (iii) | 6.4 g |
| (d) | 88 g of CO2 | (iv) | 67.2 litres at STP |
Choose the correct answer from the options given below:
| (a) | (b) | (c) | (d) | |
| 1. | (i) | (iii) | (iv) | (ii) |
| 2. | (iii) | (i) | (iv) | (ii) |
| 3. | (iv) | (i) | (ii) | (iii) |
| 4. | (iii) | (i) | (ii) | (iv) |
Subtopic: Moles, Atoms & Electrons |
50%
Level 3: 35%-60%
NEET - 2022
Hints
The mass of a 2.5 mL solution (the density of the solution is 2.15 g/mL) in the correct significant figures is:
| 1. | 5375 × 10–3 g | 2. | 5.4 g |
| 3. | 5.38 g | 4. | 53.75 g |
Subtopic: Introduction |
73%
Level 2: 60%+
NEET - 2022
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What fraction of Fe exists as Fe(III) in Fe0.96O?
(Consider Fe0.96 to be made up of Fe(II) and Fe(III) only)
1. \(\dfrac{1}{12}\)
2. \(0.08\)
3. \(\dfrac{1}{16}\)
4. \(\dfrac{1}{20}\)
(Consider Fe0.96 to be made up of Fe(II) and Fe(III) only)
1. \(\dfrac{1}{12}\)
2. \(0.08\)
3. \(\dfrac{1}{16}\)
4. \(\dfrac{1}{20}\)
Subtopic: Moles, Atoms & Electrons |
Level 3: 35%-60%
NEET - 2022
Hints
The mass of CO2 produced by heating 20 g of 20% pure limestone, as per the equation given below, is:\(\mathrm{CaCO}_3(\mathrm{~s}) \xrightarrow{\text { heat }} \mathrm{CaO}(s)+\mathrm{CO}_2(\mathrm{~g})\)
| 1. | 1.32 g | 2. | 1.12 g |
| 3. | 1.76 g | 4. | 2.64 g |
Subtopic: Equation Based Problem |
75%
Level 2: 60%+
NEET - 2023
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