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Q. No.Subtopic: Resonance & Nature of Compounds |
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Level 1: 80%+
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In the anion HCOO- the two carbon-oxygen bonds are found to be of equal length. What is the reason for it?
| 1. | Electronic orbits of the carbon atom are hybridized |
| 2. | The C = O bond is weaker than the C - O bond |
| 3. | The anion HCOO- has two resonating structures |
| 4. | The anion is obtained by removal of a proton from the acid molecule |
Subtopic: Resonance & Nature of Compounds |
87%
Level 1: 80%+
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Consider the \(H_2O_2 \) and \(O_2F_2 \) molecules where X and Y are O-O bond length in \(H_2O_2 \) and \(O_2F_2 \) respectively.
Compare X and Y.
1. X > Y
2. X < Y
3. X = Y
4. X and Y cannot be compared
Compare X and Y.
1. X > Y
2. X < Y
3. X = Y
4. X and Y cannot be compared
Subtopic: Resonance & Nature of Compounds |
60%
Level 2: 60%+
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Given below are two statements :
| Assertion (A): |
Experimentally, the oxygen-oxygen bond lengths in O₃ (ozone) are identical and lie between the bond length of an O=O double bond and an O–O single bond. |
| Reason (R): | The lone pair-lone pair repulsion between oxygen atoms is the sole reason why the bond length in ozone is shorter than a double bond (O=O) but longer than a single bond (O–O). |
| 1. | (A) is True but (R) is False |
| 2. | (A) is False but (R) is True |
| 3. | Both (A) and (R) are True and (R) is the correct explanation of (A) |
| 4. | Both (A) and (R) are True but (R) is not the correct explanation of (A) |
Subtopic: Resonance & Nature of Compounds |
66%
Level 2: 60%+
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- 1(current)
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