A point starts moving in a straight line with a certain acceleration. At a time 't' after beginning of motion the acceleration suddenly becomes retardation of the same value. The time in which the point returns to the initial point is-

1. 2t

2. 2+2t

3. t2

4. Cannot be predicted unless acceleration is given

Subtopic:  Uniformly Accelerated Motion |
 69%
From NCERT
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Referring to a-s diagram as shown in the figure. Find the velocity of the particle when the particle just covers 20 m (v0=50m s-1).

1. 350m s-1

2. 300m s-1

3. 100m s-1

4. 10m s-1

Subtopic:  Non Uniform Acceleration |
 61%
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For acceleration of a particle varies with time as shown in the figure. Calculate the displacement of the particle in the time interval from t=2 s to t=4 s.

1. 203m

2. 20 m

3. 10 m

4. 103m

Subtopic:  Non Uniform Acceleration |
 59%
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Two bodies, \(A\) (of mass \(1~\text{kg}\)) and \(B\) (of mass \(3~\text{kg}\)) are dropped from heights of \(16~\text{m}\) and \(25~\text{m}\), respectively. The ratio of the time taken by them to reach the ground is:
1. \(\frac{5}{4}\)
2. \(\frac{12}{5}\)
3. \(\frac{5}{12}\)
4. \(\frac{4}{5}\)

Subtopic:  Uniformly Accelerated Motion |
 80%
From NCERT
AIPMT - 2006
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A particle moves along a straight line OX. At a time t (in seconds), the displacement x (in metres) of the particle from O is given by x= 40 + 12t – t3. How long would the particle travel before coming to rest?

1. 24 m 2. 40 m
3. 56 m 4. 16 m
Subtopic:  Instantaneous Speed & Instantaneous Velocity |
From NCERT
AIPMT - 2006
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A particle moving along the x-axis has acceleration \(f,\) at time \(t,\) given by, \(f=f_0\left ( 1-\frac{t}{T} \right ),\)  where \(f_0\) and \(T\) are constants. The particle at \(t=0\) has zero velocity. In the time interval between \(t=0\) and the instant when \(f=0,\) the particle’s velocity \( \left ( v_x \right )\) is:
1. \(f_0T\)
2. \(\frac{1}{2}f_0T^{2}\)
3. \(f_0T^2\)
4. \(\frac{1}{2}f_0T\)

Subtopic:  Non Uniform Acceleration |
 57%
From NCERT
AIPMT - 2007
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A car moves from \(\mathrm{X}\) to \(\mathrm{Y}\) with a uniform speed \(\mathrm{v_u}\) and returns to \(\mathrm{X}\) with a uniform speed \(\mathrm{v_d}.\) The average speed for this round trip is:

1. 2vdvuvd+vu

2. vuvd

3. vdvuvd+vu

4. vu+vd2

Subtopic:  Average Speed & Average Velocity |
 82%
From NCERT
AIPMT - 2007
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The position of a particle with respect to time \(t\) along the \(\mathrm{x}\)-axis is given by \(9t^{2}-t^{3}\) where x is in metre and \(t\) in second. What will be the position of this particle when it achieves maximum speed along the \(+\mathrm{x}\) direction?
1. \(32\) m
2. \(54\) m
3. \(81\) m
4. \(24\) m

Subtopic:  Non Uniform Acceleration |
 77%
From NCERT
AIPMT - 2007
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A particle shows the distance-time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point:

         

1. B
2. C
3. D
4. A

Subtopic:  Graphs |
 79%
From NCERT
AIPMT - 2008
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A particle starts its motion from rest under the action of a constant force. If the distance covered in the first \(10\) s is \(S_1\) and that covered in the first \(20\) s is \(S_2\), then:
1. \(S_2=2S_1\)
2. \(S_2 = 3S_1\)
3. \(S_2 = 4S_1\)
4. \(S_2= S_1\)

Subtopic:  Acceleration |
 70%
From NCERT
AIPMT - 2009
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