Among the following, the strongest base is:

1. C6H5NH2

2. p-NO2-C6H4NH2

3. m-NO2-C2H4NH2

4. C2H5CH2NH2

Subtopic:  Amines - Preparation & Properties |
 79%
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A nitrogenous substance X is treated with HNO2 and the product so formed is further treated with NaOH solution, which produces blue colouration. X can be:

1. CH3CH2NH2

2. CH3CH2NO2

3. (CH3)2C(N=O)(NO2)

4. (CH3)2CHNO2

Subtopic:  Urea & Nitro Compound |
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Alkanamide that gives 1-phenylethylamine on Hoffmann's reaction is:

1. 2-Phenylpropanamide

2. 3-Phenylpropanamide

3. 2-Phenylethanamide

4. N-Phenylethanamide

Subtopic:  Amines - Preparation & Properties |
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The IUPAC name of the given comound is -

  

1. 1-Methyl-aminopropane

2. Butan-2-amine

3. 2-Methyl-2-aminopropane

4. None of the above

Subtopic:  Amines - Preparation & Properties |
 64%
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The correct order of increasing reactivity of C-X bond towards nucleophile in the following compound is

[2010]

1. I<II<IV<III

2. II<III<I<IV

3. IV<III<I<II

4. III<II<I<IV

Subtopic:  Amines - Preparation & Properties |
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Aniline is reacted with bromine water and the resulting product is treated with an aqueous solution of sodium nitrite in presence of dilute hydrochloric acid. The compound so formed is converted into a tertafluoroborate which is subsequently heated. The final product is    

1. 1,3,5-tribromobenzene

2. p-bromofluorobenzene

3. p-bromoaniline

4. 2,4,6-tribromofluorobenzene

Subtopic:  Amines - Preparation & Properties |
 74%
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Alkyl halide (RX) on treatment with KCN followed by reduction leads to the formation of:

1. RNH2

2. RCH2NH2

3. RH + NH3

4. RCH3 + N2

Subtopic:  Cyanides & Isocyanides |
 89%
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The end product in the following sequence of reactions is -

C2H5NH2HNO2A PCl5BNH3C?

1. Ethyl cyanide

2. Ethylamine

3. Methylamine

4. Acetamide

Subtopic:  Amines - Preparation & Properties |
 81%
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The product[A] formed in the reaction; 2C5H5-CNEt2ONa [A] is:C

1. 

2. 

3. 

4. 

Subtopic:  Amines - Preparation & Properties |
 53%
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CH3CH2NH2 contains a basic NH2 group, but CH3CONH2 does not, because;

1. acetamide is amphoteric in character

2. in CH3CH2NH2 the electron pair on N-atom is delocalized by resonance

3. in CH3CH2NH2 there is no resonance, while in acetamide the lone pair of electron on N-atom is delocalized and therefore less available for protonation

4. none of the above

Subtopic:  Diazonium Salts: Preparation, Properties & Uses |
 80%
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