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NEET Physics Nuclei Questions Solved

If an electron and a positron annihiliate, then the energy released is
(a) $3.2 \times 10^{- 13} J$ (b) $1.6 \times 10^{- 13} J$
(c) $4.8 \times 10^{- 13} J$ (d) $6.4 \times 10^{- 13} J$

(b) Mass of electron = mass of positron = $9.1 \times 10^{- 31}$ kg
Energy released $E = (2 m) c^{2}$
= $2 \times 9.1 \times 10^{- 31} \times (3 \times 10^{8})^{2} = 1.6 \times 10^{- 13} J$

Difficulty Level:

(1)
35%
(2)
40%
(3)
15%
(4)
10%

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