A tuning fork A of frequency 200 Hz is sounded with fork B, the number of beats per second is 5. By putting some wax on A, the number of beats increases to 8. The frequency of fork B is :

(1) 200 Hz

(2) 195 Hz

(3) 192 Hz

(4) 205 Hz

Subtopic:  Beats |
 70%
From NCERT
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Two tuning forks have frequencies 380 and 384 Hz respectively. When they are sounded together, they produce 4 beats. After hearing the maximum sound, how long will it take to hear the minimum sound?

(1) 12sec

(2) 14sec

(3) 18sec

(4) 116sec

Subtopic:  Beats |
From NCERT
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A couple of tuning forks produces 2 beats in the time interval of 0.4 seconds. So the beat frequency is :

(1) 8 Hz

(2) 5 Hz

(3) 2 Hz

(4) 10 Hz

Subtopic:  Beats |
 78%
From NCERT
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It is possible to hear beats from the two vibrating sources of frequency :

(1) 100 Hz and 150 Hz

(2) 20 Hz and 25 Hz

(3) 400 Hz and 500 Hz

(4) 1000 Hz and 1500 Hz

Subtopic:  Beats |
 83%
From NCERT
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Two sound waves of wavelengths 5m and 6m formed 30 beats in 3 seconds. The velocity of sound is :

(1) 300 ms–1

(2) 310 ms–1

(3) 320 ms–1

(4) 330 ms–1

Subtopic:  Beats |
 66%
From NCERT
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Two sound sources when sounded simultaneously produce four beats in 0.25 seconds. The difference in their frequencies must be :

(1) 4

(2) 8

(3) 16

(4) 1

Subtopic:  Beats |
 73%
From NCERT
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Two strings X and Y of a sitar produce a beat frequency 4 Hz. When the tension of the string Y is slightly increased the beat frequency is found to be 2 Hz. If the frequency of X is 300 Hz, then the original frequency of Y was :

(1) 296 Hz

(2) 298 Hz

(3) 302 Hz

(4) 304 Hz

Subtopic:  Beats |
 72%
From NCERT
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Two vibrating tuning forks produce progressive waves given by Y1=4sin500πt and Y2=2sin506πt. Number of beats produced per minute is :

(1) 360

(2) 180

(3) 3

(4) 60

Subtopic:  Beats |
 57%
From NCERT
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The disc of a siren containing 60 holes rotates at a constant speed of 360 rpm. The emitted sound is in unison with a tuning fork of frequency :

(1) 10 Hz

(2) 360 Hz

(3) 216 Hz

(4) 6 Hz

Subtopic:  Standing Waves |
 58%
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The distance between the nearest node and antinode in a stationary wave is :

(1) λ

(2) λ2

(3) λ4

(4) 2λ

Subtopic:  Standing Waves |
 82%
From NCERT
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