Two waves are propagating to the point P along a straight line produced by two sources A and B of simple harmonic and of equal frequency. The amplitude of every wave at P is ‘a’ and the phase of A is ahead by π/3 than that of B and the distance AP is greater than BP by 50 cm. Then the resultant amplitude at the point P will be, if the wavelength is 1 meter  is -

(1) 2a

(2) $a\sqrt{3}$

(3) $a\sqrt{2}$

(4) a

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The minimum intensity of sound is zero at a point due to two sources of nearly equal frequencies, when :

(1) Two sources are vibrating in opposite phase

(2) The amplitude of the two sources are equal

(3) At the point of observation, the amplitudes of two S.H.M. produced by two sources are equal and both the S.H.M. are along the same straight line

(4) Both the sources are in the same phase

Concept Questions :-

Beats
High Yielding Test Series + Question Bank - NEET 2020

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Two sound waves (expressed in CGS units) given by ${y}_{1}=0.3\mathrm{sin}\frac{2\pi }{\lambda }\left(vt-x\right)$ and ${y}_{2}=0.4\mathrm{sin}\frac{2\pi }{\lambda }\left(vt-x+\theta \right)$ interfere. The resultant amplitude at a place where the phase difference is π/2 will be :

(1) 0.7 cm

(2) 0.1 cm

(3) 0.5 cm

(4) $\frac{1}{10}\sqrt{7}\text{\hspace{0.17em}}cm$

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

If two waves having amplitudes 2A and A and same frequency and velocity, propagate in the same direction in the same phase, the resulting amplitude will be

(1) 3A

(2) $\sqrt{5}A$

(3) $\sqrt{2}A$

(4) A

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The intensity ratio of the two waves is 1 : 16. The ratio of their amplitudes is

(1) 1 : 16

(2) 1 : 4

(3) 4 : 1

(4) 2 : 1

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The superposing waves are represented by the following equations : ${y}_{1}=5\mathrm{sin}2\pi \left(10\text{\hspace{0.17em}}t-0.1x\right)$, ${y}_{2}=10\mathrm{sin}2\pi \left(20\text{\hspace{0.17em}}t-0.2x\right)$ Ratio of intensities $\frac{{I}_{\mathrm{max}}}{{I}_{\mathrm{min}}}$ will be :

(1) 1

(2) 9

(3) 4

(4) 16

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The displacement of a particle is given by $x=3\mathrm{sin}\left(5\pi \text{\hspace{0.17em}}t\right)+4\mathrm{cos}\left(5\pi \text{\hspace{0.17em}}t\right)$. The amplitude of the particle is :

(1) 3

(2) 4

(3) 5

(4) 7

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The two interfering waves have intensities in the ratio 9 : 4. The ratio of intensities of maxima and minima in the interference pattern will be :

(1) 1 : 25

(2) 25 : 1

(3) 9 : 4

(4) 4 : 9

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

If the ratio of amplitude of two waves is 4 : 3. Then the ratio of maximum and minimum intensity will be :

(1) 16 : 18

(2) 18 : 16

(3) 49 : 1

(4) 1 : 49

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Equation of motion in the same direction is given by ${y}_{1}=A\mathrm{sin}\left(\omega t-kx\right)$, ${y}_{2}=A\mathrm{sin}\left(\omega t-kx-\theta \right)$. The amplitude of the medium particle will be

(1) $2A\mathrm{cos}\frac{\theta }{2}$

(2) $2A\mathrm{cos}\theta$

(3) $\sqrt{2}A\mathrm{cos}\frac{\theta }{2}$

(4) $1.2f,\text{\hspace{0.17em}}1.2\lambda$

Concept Questions :-

Wave motion