A current-carrying closed loop in the form of a right-angle isosceles triangle ABC is placed in a uniform magnetic field acting along AB. If the magnetic force on the arm BC is F, the force on the arm AC is:

                         

1. -F                                               2. F

3. 2F                                             4. -2F

Subtopic:  Force between Current Carrying Wires | Current Carrying Loop: Force & Torque |
 64%
From NCERT
NEET - 2011
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A galvanometer of resistance, G is shunted by a resistance S ohm. To keep the main current in the circuit unchanged, the resistance to be put in series with the galvanometer is

(1) S2(S+G)                                             

(2) SG(S+G)

(3) G2(S+G)                                             

(4) G(S+G)

Subtopic:  Moving Coil Galvanometer |
From NCERT
NEET - 2011
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A square loop, carrying a steady current I, is placed in a horizontal plane near a long straight conductor carrying a steady current I1 at a distance d from the conductor as shown in figure. The loop will experience 

                    

(1) a net repulsive force away from the conductor 

(2) a net torque acting upward perpendicular to the horizontal plane

(3) a net torque acting downward normal to the horizontal plane

(4) a net attractive force towards the conductor 

Subtopic:  Force between Current Carrying Wires |
 78%
From NCERT
NEET - 2011
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Charge q is uniformly spread on a thin ring of radius R. The ring rotates about its axis with a uniform frequency f Hz. The magnitude of magnetic induction at the center of the ring is :

(1) μ0q f2R                                       

(2) μ0q2fR

(3) μ0q2πfR                                       

(4) μ0q f2πR

Subtopic:  Magnetic Field due to various cases |
 76%
From NCERT
NEET - 2011
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A beam of cathode rays is subjected to crossed Electric (E) and magnetic fields(B). The fields are adjusted such that the beam is not deflected. The specific charge of the cathode rays is given by:

1. B22VE2                                             

2. 2VB2E2

3. 2VE2B2                                           

4. E22VB2

(where V is the potential difference between cathode and anode)

Subtopic:  Lorentz Force |
 58%
From NCERT
NEET - 2010
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A galvanometer has a coil of resistance 100Ω and gives a full scale deflection for 30 mA current.If it is to work as a voltmeter of 30V range, the resistance required to be added will be 

(1) 900 Ω                                     

(2) 1800 Ω

(3) 500 Ω                                     

(4) 1000 Ω

Subtopic:  Conversion to Ammeter & Voltmeter |
 80%
From NCERT
NEET - 2010
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A square current carrying loop is suspended in a uniform magnetic field acting in the plane of the loop. If the force on one arm of the loop is F, the net force on the remaining three arms of the loop is

1. 3F                 

2. -F

3. -3F               

4.  F

Subtopic:  Current Carrying Loop: Force & Torque |
 83%
From NCERT
NEET - 2010
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A current loop consists of two identical semicircular parts each of radius \(R\), one lying in the x-y plane, and the other in the x-z plane. If the current in the loop is \(i\), what will be the resultant magnetic field due to the two semicircular parts at their common centre?

1. \( \frac{\mu_0 i}{2 \sqrt{2} R} \) 2. \( \frac{\mu_0 i}{2 R} \)
3. \( \frac{\mu_0 i}{4 R} \) 4. \( \frac{\mu_0 i}{\sqrt{2} R}\)

Subtopic:  Magnetic Field due to various cases |
 65%
From NCERT
NEET - 2010
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A closely wound solenoid of 2000 turns and area of cross-section 1.5×10-4 m2 carries a current of 2.0 A. It is suspended through its centre and perpendicular to its length, allowing it to turn in a horizontal plane in a uniform magnetic field 5×10-2 T making an angle of 30° with the axis of the solenoid. The torque on the solenoid will be

(1) 3×10-3 Nm                                 

(2) 1.5×10-3 Nm

(3) 1.5×10-2 Nm                               

(4) 3×10-2 Nm

Subtopic:  Magnetic Moment |
 73%
From NCERT
NEET - 2010
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A particle having a mass of 10-2 kg carries a charge of 5×10-8 C. The particle is given an initial horizontal velocity of 105 ms-1 in the presence of electric field E and magnetic field B. To keep the particle moving in a horizontal direction, it is necessary that

(1) B should be perpendicular to the direction of velocity and E should be along the direction of velocity.

(2) Both B and E should be along the direction of velocity.

(3) Both B and E are mutually perpendicular and perpendicular to the direction of velocity.

(4) B should be along the direction of velocity and E should be perpendicular to the direction of velocity.

Which one of the following pairs of statements are possible?

1.   (1) and (3)                                       2.    (3) and (4)

3.   (2) and (3)                                       4.   (2) and (4)

Subtopic:  Lorentz Force |
 54%
From NCERT
NEET - 2010
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