NEET Physics Nuclei Questions Solved

NEET - 2013

A certain mass of hydrogen is changed to helium by the process of fusion. The man defect in fusion reaction is 0.02866 u. The energy liberated per u is (given 1 u = 931 MeV)

(a) 2.67 MeV

(b) 26.7 MeV

(c) 6.675 MeV

(d) 13.35 MeV

(c) Here,Δm=0.02866U

∴ Energy liberated

=0.02866 x 931/4

=26.7/4 MeV

=6.675MeV

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