A potentiometer wire has a length 4 m and resistance 8Ω. The resistance that must be connected in series with the wire and an accumulator of emf 2V, so as to get a potential gradient 1mV per cm of the wire is 

(1)32Ω

(2)40Ω

(3)44Ω

(4)48Ω 

Subtopic:  Meter Bridge & Potentiometer |
 67%
From NCERT
NEET - 2015
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A, B, and C are voltmeters of resistance R, 1.5R, and 3R respectively as shown in the figure. When some potential difference is applied between X and Y, the voltmeter readings are VA, VB, and VC respectively. Then,


1. VA=VB=VC

2. VA≠VB=VC

3. VA=VB≠VC

4. VA≠VB≠VC

Subtopic:  EMF & Terminal Voltage |
 60%
From NCERT
NEET - 2015
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A potentiometer wire of length L and a resistance r are connected in series with a battery of e.m.f. Eo and a resistance r1. An unknown e.m.f. is balanced at a length l of the potentiometer wire. The e.m.f. E will be given by

(1)EorLr1l

(2)Eorlr+r1L

(3)Eol/L

(4)EorLr+r1l

Subtopic:  Meter Bridge & Potentiometer |
 73%
From NCERT
NEET - 2015
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Two cities are 150 km apart. Electric power is sent from one city to another city through copper wires. The fall of potential per km is 8V and the  average resistance per km is 0.5 Ω. The power loss in the wire is

(1) 19.2W

(2) 19.2kW

(3) 19.2J

(4) 12.2kW 

Subtopic:  Heating Effects of Current |
 82%
From NCERT
NEET - 2014
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The resistances in the two arms of the meter bridge are 5 and R , respectively. When the resistance R is shunted with an equal resistance, the new balance point is at 1.6l1. The resistance R, is


(1)10Ω

(2)15Ω

(3)20Ω

(4)25Ω 


Subtopic:  Kirchoff's Voltage Law |
 71%
From NCERT
NEET - 2014
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A potentiometer circuit has been setup for finding the internal resistance of a given cell. The main battery, used across the potentiometer wire, has an emf of 2.0 V and a negligible internal resistance. The potentiometer wire itself is 4 m long. When the resistance, R, connected across the given cell, has values of

(i)infinity

(ii)9.5Ω 

the 'balancing lengths', on the potentiometer wire are found to be 3m and 2.85m, respectively. The value of internal resistance of the cell is

(1) 0.25Ω 

(2) 0.95Ω 

(3) 0.5Ω 

(4) 0.75Ω  

Subtopic:  Meter Bridge & Potentiometer |
 68%
From NCERT
NEET - 2014
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A wire of resistance 4Ω is stretched to twice its original length. The resistance of a stretched wire would be :

(1)2Ω

(2)4Ω

(3)8Ω

(4)16Ω 

Subtopic:  Combination of Resistors |
 82%
From NCERT
NEET - 2013
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The internal resistance of a 2.1V cell which gives a current of 0.2A through a resistance of 10Ω is :

(1)0.2Ω

(2)0.5Ω

(3)0.8Ω

(4)1.0Ω

Subtopic:  EMF & Terminal Voltage |
 87%
From NCERT
NEET - 2013
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The resistances of the four arms P, Q,R and S in a Wheatstone's bridge are 10Ω ,30Ω ,30Ω and 90Ω, respectively. The emf and internal resistance of the cell are 7 V and 5 Ω respectively. If the galvanometer resistance is 50Ω, the current drawn from the cell will be

(1) 1.0A

(2) 0.2A

(3) 0.1A

(4) 2.0A



Subtopic:  Wheatstone Bridge |
 78%
From NCERT
NEET - 2013
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In the circuit shown the cells A and B have negligible resistances. For VA=12V, R1=500Ω and R=100Ω the galvanometer (g) shown no deflection.The value of VB is 

(a)4V                                         (b)2V

(c)12V                                       (d)6V

Subtopic:  Kirchoff's Voltage Law |
 73%
From NCERT
NEET - 2012
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