NEET Questions Solved


One 10 V, 60 W bulb is to be connected to 100 V line. The required induction coil has self inductance of value (f = 50 Hz) 

(1) 0.052 H

(2) 2.42 H

(3) 16.2 mH

(4) 1.62 mH

(1) Current through the bulb i=PV=6010=6A

V=VR2+VL2

(100)2=(10)2+VL2  VL=99.5  Volt

Also VL=iXL=i×(2πνL)

99.5=6×2×3.14×50×L

  L=0.052  H

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