The van't Hoff factor, i for a compound which undergoes dissociation in one solvent and

association in other solvent is respectively.

1. less than one and less than one

2. greater than one and less than one

3. greater than one and greater than one

4. less than one and greater than one

Subtopic:  Van’t Hoff Factor |
 81%
From NCERT
NEET - 2011
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An aqueous solution is 1.00 molal in KI. Which change will cause the vapour pressure of

the solution to increase ?

1. Addition of NaCl

2. Addition of Na2SO4

3. Addition of 1.00 molal KI

4. Addition of water

Subtopic:  Relative Lowering of Vapour Pressure |
 55%
From NCERT
NEET - 2010
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A solution of sucrose (molar mass = 342 g mol-1) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water.

The freezing point of the solution obtained will be:

 (Kf for water = 1.86 K kg mol-1)

1. -0.372 °C

2. 0.372 °C

3. 0.572 °C

4. -0.572 °C

Subtopic:  Depression of Freezing Point |
 71%
From NCERT
NEET - 2010
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A 0.0020 m aqueous solution of an ionic compound Co(NH3)5(NO2)Cl freezes at -0.00732°C. Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be (kf=-1.86°C/ m)

1. 2

2. 3

3. 4

4. 1

 

Subtopic:  Depression of Freezing Point |
 66%
From NCERT
NEET - 2009
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0.5 molal aqueous solution of a weak acid (HX) is 20% ionised. If Kf for water is 1.86 K kg mol-1, the lowering in freezing point of the solution is:

(1) -1.12 K

(2) 0.56 K

(3) 1.12 K

(4) - 0.56 K

Subtopic:  Depression of Freezing Point |
 50%
From NCERT
NEET - 2007
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1.00 g of a non-electrolyte solute (molar mass 250g/mol) was dissolved in 51.2 g of benzene. If the freezing point depression constant, Kf of benzene is 5.12 K kg mol-1, the freezing point of benzene will be lowered by:-

(1) 0.4 K

(2) 0.3 K

(3) 0.5 K

(4) 0.2 K

Subtopic:  Depression of Freezing Point |
 79%
From NCERT
NEET - 2006
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A solution of acetone in ethanol:

1. Shows a negative deviation from Raoult's law.

2. Shows a positive deviation from Raoult's law.

3. Behaves like a near ideal solution.

4. Obeys Raoult's law.

Subtopic:  Raoult's Law |
 73%
From NCERT
NEET - 2006
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Three solutions are prepared by adding 'w' gm of 'A' into 1kg of water, 'w' gm of 'B' into another 1 kg of water and 'w' gm of 'C' in another 1 kg of water (A, B, C are non electrolytic). Dry air is passed from these solutions in sequence (A → B → C). The loss in weight of solution A was found to be 2gm while solution B gained 0.5 gm and solution C lost 1 gm. Then the relation between molar masses of A, B and C is :

(1) MA: MB : Mc = 4 : 3 : 5

(2) MA : MB: Mc = 14:13:15

(3) Mc > MA > MB

(4) MB > MA> Mc

Subtopic:  Relative Lowering of Vapour Pressure |
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How many mili moles of sucrose should be dissolved in 500 gms of water so as to get a solution which has a difference of 103.57°C between boiling point and freezing point.

(K1 = 1.86 K Kg mol−1, Kb = 0.52 K Kg mo1−1)

(1) 500 mmoles

(2) 900 mmoles

(3) 750 mmoles

(4) 650 mmoles

Subtopic:  Elevation of Boiling Point |
 58%
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The molar heat of vapourization of toluene is AHv. If its vapour pressure at 315 K is 60 torr & that at 356K is300 torr then AHv = ? (log 2 = 0.3)

(1) 37.5 kJ/mole

(2) 3.75 kJ/mole

(3) 37.5 J/mol

(4) 3.75 J/mole

Subtopic:  Relative Lowering of Vapour Pressure |
 50%
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