Ph-CHlOH-CH3PCC(A)NH2-NH-CO-NH2(B)

Product (B) is :

1.  Ph-ClCH3=N-NH-CllO-NH2

2. Ph-ClCH3=N-CllO-NH-NH2

3. Ph-CH=N-NlCH3-CllO-NH2

4. Ph-CHlCH3-NH-CllO-NH-NH2

Subtopic:  Aldehydes & Ketones: Preparation & Properties |
 65%
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(A) and (B) is differentiated by :

1. NaH

2. 2-4 DNP

3. Tollen's reagent 

4. NaHSO3

Subtopic:  Aldehydes & Ketones: Preparation & Properties |
 79%
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CH2CH2CO2H BaCO3 ANH2NH2 BKOHheat (C),
 |
CH2CH2CO2H

Product (C) obtained is :

(a) CH3-CH=CH-CH2

 (b)

  (c) 

 (d)

Subtopic:  Carboxylic Acids: Preparation & Properties |
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1. 

2. 

3. 

4. 

Subtopic:  Aldehydes & Ketones: Preparation & Properties |
 57%
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CH3-CO-HHCN(A)H3O(B)(C)LiAlH4(D)HIO4HCHO + (E)

Compound (C) can show geometrical isomerism, Product (E) of the reaction will be :

(1) CH3-CO-CH3

(2) CH3-CH2-CO-H

(3) CH3-CHO

(4) HCHO

Subtopic:  Aldehydes & Ketones: Preparation & Properties |
 63%
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Arrange in their increasing order of equilibrium constants for hydraion ?

(1) CH3-C(A)O-CH3,     CH3-C(B)O-H,   CH3-C (C)O-CH2-Cl,   H-C(D)O-H,   Cl-CH2(E)-CO-H

(a) A < B < C < D < E

(2) A < C < B < E < D

(3) A < C < E < B < D

(4) C < A < B < E < D

Subtopic:  Isomers & Reaction Mechanism |
 61%
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Ph-CH2-CN(2)CH3-CO-Cl(3) H3O/(1)EtONA (P); Product (p) of the reaction will be :

(a) Ph-CH2-CO-H

(b) Ph-CH2-CO-CH3

(c) Ph-CHCH3l-CO-H

(d) Ph-CHCH3l-CO-CH3

Subtopic:  Aldehydes & Ketones: Preparation & Properties |
 60%
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1. 

2. 

3. 

4. 

Subtopic:  Aldehydes & Ketones: Preparation & Properties |
 56%
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(A)Symmetrical ketone LiAlH4(B)H Diastereomers Reactent (A) is :

(a) CH3-CO-CH3

(b) CH3-CO-CH2-CH3
(c) CH3-CH2-CO-CH2-CH3

(d) CH3-CH2-CH2-CH=O

Subtopic:  Aldehydes & Ketones: Preparation & Properties |
 65%
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Molecular weight of compound (A) is:

(1) 58

(2) 120

(3) 60

(4) 182

Subtopic:  Acid Derivatives - Preparation, Properties & Uses |
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