NEET Questions Solved


Two sources of equal emf are connected to an external resistance R. The internal resistances of the two sources are R1 and R2(R2>R1). If the potential difference across the source having internal resistance R2 is zero, then 

(1) R=R1R2/(R1+R2)

(2) R=R1R2/(R2R1)

(3) R=R2×(R1+R2)/(R2R1)

(4) R=R2R1

(4) i=2ER+R1+R2

From cell (2) E=V+iR2=0+iR2

E=2ER+R1+R2×R2R=R2R1

Difficulty Level:

  • 11%
  • 42%
  • 18%
  • 32%