CuSO4 solution is treated separately with KCl and KI. In which case, Cu+2 will be reduced to Cu ?

(1) with KCl

(2) with KI

(3) with KCl and KI both

(4) None of these

Subtopic:  Electrode & Electrode Potential |
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How many coulombs are required to oxidise 1 mol H2O2 to O2 ?

(1) 9.65 X 104 C

(2) 9.3 X 104 C

(3) 1.93 X 105 C

(4) 19.3 X 102 C

Subtopic:  Faraday’s Law of Electrolysis |
 62%
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The quantity of electricity required to reduce 12.3 g of nitrobenzene to aniline with 50 % current efficiency is:

1. 1 F

2. 0.6 F

3. 0.5 F

4. 1.2 F

Subtopic:  Faraday’s Law of Electrolysis |
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Electrolysis of hot aqueous solution of NaCl gives NaClO4 as-

NaCl +4H2O           NaClO4 + 4H2

How many faraday are required to obtain 1000 g of sodium perchlorate ?

(1) 66 F

(2) 122.5 F

(3) 15.13 F

(4) 1.86 F

Subtopic:  Faraday’s Law of Electrolysis |
 59%
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The cell reaction of micro electrochemical cell formed during rusting of iron is:-

1.  O2(g) + 4H(aq)  + 4e-  2H2O (l)

2. 4Fe+2(aq)  + O2(g) + 2H2O(l)  4FeO + 4H(aq)

3. 2Fe(s) + O2(g) + 4H°(aq) 2Fe+2(aq)  + 2H2O(aq)

4.  Fe(s) Fe+2(aq) + 2e-

Subtopic:  Corrosion |
 65%
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Which of the following is an incorrect statement :- 

1. Mercury cell is a primary cell providing a constant potential

2. During recharging lead storage cell works as electrolytic cell

3. Galvanised iron does not rust

4. In electrolytic cell reduction occurs at anode and in galvanic cell oxidation takes place at anode

Subtopic:  Electrochemical Series |
 72%
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For the cell reaction

Cuc1+2 (aq) +Zn(s)            ZnC2+2 (aq) + Cu(s)

the change in free energy at a given temperature is a function of 

(1) lnC1

(2) lnC2C1 

(3) ln (C1 +C2)

(4) lnC2

Subtopic:  Electrode & Electrode Potential |
 92%
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EMF of the following cell will be zero if

Pt(H2)|H+||H+|(H2)Pt

    P1   C1  C2    P2

(1) C1P1 = C2P2

(2) C1P2 = P2C1

(3) C12P2 = C22P1

(4) None of these

Subtopic:  Nernst Equation |
 50%
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ENi+2Ni0 = -0.25 V, EAu+3Au0 = 1.50 V

the emf of Voltaic cell

Ni | Ni+2(1M) || Au+3(1M) Au is:-

(1) 1.25 V

(2) -1.75 V

(3) 1.75 V

(4) 4 V

Subtopic:  Nernst Equation |
 82%
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The same amount of electric current is apassed through aqueous solution of MgSO4 and AlCl3. If 2.8 g Mg metal is deposited at amount of Al metal deposited in second cell will be

1. 2.1 g

2. 2.49 g

3. 3.15 g

4. 3.73g

Subtopic:  Faraday’s Law of Electrolysis |
 77%
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