Pick out the incorrect statement

1. Equivalent conductance increases with dilution

2. Molar conductance increases with dilution

3. Specific conductance increases with dilution

4. Specific resistance increases with dilution

Subtopic:  Conductance & Conductivity |
 65%
From NCERT
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When NaCl solution is electrolysed using Pt electrodes then pH of solution

1. Increases

2. Decreases

3. Remains same

4. Firstly increases and then decreases

Subtopic:  Relation between Emf, G, Kc & pH |
 62%
From NCERT
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By how much will the potential of half cell Cu2+| Cu change if the solution is diluted to 100 times at 298 K. It will -

1. Increase by 59 mV 2. Decrease by 59 mV
3. Increase by 29.5 mV 4. Decrease by 29.5 mV
Subtopic:  Nernst Equation |
 56%
From NCERT
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What will be the molar conductance at infinite dilution for NH4OH. If at infinite dilution the molar conductances of Ba(OH)2, BaCl2 and NH4Cl are 523.28, 280.0 and 129.8 ohm-1 cm-1 mol-1 respectively.
1. 502.88
2. 373.68
3. 251.44
3. 226.96

Subtopic:   Kohlrausch Law & Cell Constant |
 57%
From NCERT
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At 25°C the specific conductance of sturated solution of AgCl is 2.3 X 10-6 ohm-1cm-1. What will be the solubility of AgCl at 25°C if ionic conductances of Ag and Cl at infinite dilution are 61.9 and 76.3 ohm-1cm2mol-1 respectively.

1. 1.66 X 10-11M

2. 3.18 X 10-6M

3. 6.01 X 10-5M

4. 1.66 X 10-5M

Subtopic:   Kohlrausch Law & Cell Constant |
 58%
From NCERT
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2Ag(aq) + Cu(s)            Cu(aq)+2 + 2Ag(s)

The cell potential for this reaction is 0.46V. Which of the following change will increase the potential the most ?

(1) [Ag] concentration is doubled

(2) [Cu2+] concentration is halved

(3) Size of Cu(s) electrode is doubled

(4) size of Ag(s) electrode is decreased to half

Subtopic:  Electrochemical Series |
 73%
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What will be the value of G° for the rection Cu+2 + Fe             Fe+2 + Cu , 

if ECu+2Cu = +0.34 V and EFe+2Fe = -0.44 V

(1) -65.62 KJ

(2) -75.27 KJ

(3) -150.54 KJ

(4) +150.54 KJ

Subtopic:  Electrode & Electrode Potential |
 77%
From NCERT
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At 298 K the Emf of the following cell is:-

\(\small{Pt|H_{2}(1 \ atm)|H^{+}(0.02 \ M) \ || \ H^{+}(0.01 \ M)|H_{2}(1 \ atm)|Pt}\)

1. - 0.017 V

2. 0.0295 V

3. 0.1 V

4. 0.059 V

Subtopic:  Nernst Equation |
 58%
From NCERT
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At 25°C temperature Zn electrode is placed in 0.1M solution of zinc salt then what will be the reduction potential ? If it is assumed that salt dissociates 25% at this dilution (EZn2+Zn° = -0.76 V)

(1) -0.713 V

(2) - 0.81 V

(3) + 0.778 V

(4) - 0.84 V

Subtopic:  Nernst Equation |
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The reduction potential of Hydrogen electrode is -118mV then the concentration of Hion in solution will be :-

(1) 10-4M

(2) 2M

(3) 0.01M

(4) 10-3M

Subtopic:  Nernst Equation |
 62%
From NCERT
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