An electron and a proton are moving under the influence of mutual forces. In calculating the change in the kinetic energy of the system during motion, one ignores the magnetic force of one on another. This is because:

1. the two magnetic forces are equal and opposite, so they produce no net effect.

2. the magnetic forces do no work on each particle.

3. the magnetic forces do equal and opposite (but nonzero) work on each particle.

4. the magenetic forces are necessarily negligible.

Subtopic:  Lorentz Force |
From NCERT
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Only the current inside the Amperian loop contributes in:

1. finding magnetic field at any point on the Ampere's loop

2. line integral of magnetic field

3. in both of the above

4. in neither of them

Subtopic:  Ampere Circuital Law |
From NCERT
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Consider the three closed loops drawn using solid line in the magnetic field (magnetic field lines are drawn using dotted line) of an infinite curent-carrying wire normal to the plane of paper as shown.

Rank the line integral of the magnetic field along each path in order of increasing magnitude:

1. 1 > 2 > 3

2. 1 = 3 > 2

3. 1 = 2 = 3

4. 3 > 2 > 1

Subtopic:  Ampere Circuital Law |
 53%
From NCERT
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Electrons moving with different speeds enter in uniform magnetic field in a direction perpendicular to the field. If they move along circular paths, then the time periods of rotation will be:

1. same for all electrons

2. greater for the faster electrons

3. smaller for the faster electrons

4. either 2 or 3 depending on the magnitude of the magnetic field

Subtopic:  Lorentz Force |
 70%
From NCERT
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Electrons moving with different speeds enter in uniform magnetic field in a direction perpendicular to the field. They will move along circular paths:

1. of same radius

2. with larger radius for the faster electrons

3. with smaller radius for the faster electrons

4. either 2 or 3 depending on the magnitude of the magnetic field

Subtopic:  Lorentz Force |
 67%
From NCERT
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Rank the value of B·dl for the closed paths shown in figure from the smallest to largest:

1. a, b, c, d

2. a, c, d, b

3. a, d, c, b

4. a, c, b, d

Subtopic:  Ampere Circuital Law |
 60%
From NCERT
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A direct current is passing through a wire. It is bent to form a coil of one turn. Now it is further bent to form coil of two turns but of smaller radius. The ratio of the magnetic induction at the centre of this coil and at the centre of the coil of one turn is:

1. 1: 4

2. 4: 1

3. 2: 1

4. 1: 1

Subtopic:  Magnetic Field due to various cases |
 56%
From NCERT
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A galvanometer with an internal resistance of 100Ω will show a full-scale deflection with a current of 10 mA. Which of the following circuits would turn this galvanometer into an ammeter which will read 10 A at full scale?

1. 

2. 

3. 

4. 

Subtopic:  Conversion to Ammeter & Voltmeter |
 77%
From NCERT
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A galvanometer coil has a resistance of 90 Ω and a full-scale deflection current of 10 mA. A 910 Ω resistance is connected in series with the galvanometer to make a voltmeter. If the least count of the voltmeter is 0.1 V, the number of divisions on the scale is:

1. 90

2. 91

3. 100

4. none

Subtopic:  Conversion to Ammeter & Voltmeter |
 68%
From NCERT
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Two charged particles traverse identical helical paths in a completely opposite sense in a uniform magnetic field B = B0k^.

1. They have equal z-components of momenta.

2. They must have equal charges.

3. They necessarily represent a particle-antiparticle pair.

4. The charge to mass ratio satisfy: (em)1+(em)2=0

Subtopic:  Lorentz Force |
 57%
From NCERT
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