The equivalent weight of MnSO4 is half its molecular weight when it is converted to

1. MnO

2. MnO42-

3. MnO2

4. MnO4-

Subtopic:  Equivalent Weight |
 68%
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An aqueous solution of 6.3 g oxalic acid dihydrate is made up to 250 mL. The volume of 0.1 N NaOH required to completely neutralize 10 mL of this solution is

1. 4 mL

2. 20 mL

3. 40 mL

4. 60 mL

Subtopic:  Equivalent Weight |
 57%
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KMnO4 (mol. wt=158) oxidizes oxalic acid in acidic medium to CO2 and water as follows.

5C2O42-+2MnO4-+16H+10CO2+2Mn2++8H2O

What is the equivalent weight of KMnO4?

1. 158

2. 31.6

3. 39.5

4. 79

Subtopic:  Equivalent Weight |
 78%
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Among the following, identify the species with an atom in +6 oxidation state-

1. MnO4-

2. Cr(CN)63-

3. NiF62-

4. CrO2Cl2

Subtopic:  Oxidizing & Reducing Agents |
 84%
From NCERT
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Which of the following does not represent a redox reaction?

1. Cr2O72- + 2OH- → CrO42- + H2O

2. SO42- + 2I- + 2H+ → I2 + H2S + H2O

3. Ca + 2H2O → Ca(OH)2 + H2

4. PCl5 → PCl3 + Cl2

Subtopic:  Oxidizing & Reducing Agents |
 57%
From NCERT
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The oxidation number of phosphorous in ATP (adenosine triphosphate) is -

1. 2 2. 3
3. 4 4. 5
Subtopic:  Oxidizing & Reducing Agents |
 61%
From NCERT
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The species that does not contain peroxide ions is :

(1) PbO2

(2) H2O2

(3) SrO2

(4) BaO2

Subtopic:  Introduction to Redox and Oxidation Number |
 68%
From NCERT
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What is the alteration in the oxidation state of carbon in the given reaction?

\({CH_4}_{(g)} + 4{Cl_2}_{(g)} \rightarrow {CCl_4}_{(l)} + 4 HCl_{(g)}\)

1. 0 to +4

2. -4 to +4

3. 0 to -4

4. +4 to +4

Subtopic:  Oxidizing & Reducing Agents |
 82%
From NCERT
NEET - 2020
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In the given reaction, what is the name of the species that bleaches the substances due to its oxidising action?

Cl2(g) + 2OH-(aq) → ClO-(aq) + Cl-(aq) + H2O(l)

1. ClO- 

2. Cl2

3. Cl-

4. Both ClO- and Cl-

Subtopic:  Oxidizing & Reducing Agents |
 50%
From NCERT
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MnO42- undergoes disproportionation reaction in acidic medium but MnO4- does not. It is:

1.  Due to the highest oxidation state of Mn in  MnO42-
2.  Due to the highest oxidation state of Mn in  MnO4-
3.  Due to the endothermic nature of the disproportionation reaction.
4.  Due to the exothermic nature of the disproportionation reaction.

Subtopic:  Introduction to Redox and Oxidation Number |
 81%
From NCERT
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