The time period of oscillation of a simple pendulum of length equal to half of the diameter of the earth is about 

1.  60 minute

2.  84.6 minute

3.  42.3 minute

4.  24 hour

Subtopic:  Angular SHM |
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NEET 2023 - Target Batch - Aryan Raj Singh
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The time period of the given spring-mass system is:

            
1. \(2\pi \sqrt{\frac{m}{k}}\)
2. \(2\pi \sqrt{\frac{m}{2k}}\)
3. \(2\pi \sqrt{\frac{2m}{\sqrt{3}k}}\)
4. \(\pi \sqrt{\frac{m}{k}}\)

Subtopic:  Combination of Springs |
 76%
From NCERT
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The equation of simple harmonic motion is given by X = (4 cm)sin6.28 t + 5π3then maximum velocity of the particle in simple harmonic motion is: 

1.  25.12 m/s 

2.  25.12 cm/s 

3.  12.56 m/s 

4.  12.56 cm/s

Subtopic:  Simple Harmonic Motion |
 89%
From NCERT
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A spring pendulum is on the rotating table. The initial angular velocity of the table is \(\omega_{0}\) and the time period of the pendulum is \(T_{0}.\) Now the angular velocity of the table becomes \(2\omega_{0},\) then the new time period will be:
1. 
\(2T_{0}\)
2. \(T_0\sqrt{2}\)
3. remains the same
4. \(\frac{T_0}{\sqrt{2}}\)

Subtopic:  Angular SHM |
 70%
From NCERT
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If the vertical spring-mass system is dipped in a non-viscous liquid, then:

1. only mean position is changed.
2. only the time period is changed.
3. time period and mean position both are changed.
4. time period and mean position both remain the same.
Subtopic:  Combination of Springs |
From NCERT
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The displacement \( x\) of a particle varies with time \(t\) as \(x = A sin\left (\frac{2\pi t}{T} +\frac{\pi}{3} \right)\)The time taken by the particle to reach from \(x = \frac{A}{2} \) to \(x = -\frac{A}{2} \) will be:

1. \(\frac{T}{2}\) 2. \(\frac{T}{3}\)
3. \(\frac{T}{12}\) 4. \(\frac{T}{6}\)

Subtopic:  Phasor Diagram |
 51%
From NCERT
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Force on a particle F varies with time t as shown in the given graph. The displacement x vs time t graph corresponding to the force-time graph will be:
          

1. 2.
3. 4.
Subtopic:  Linear SHM |
 66%
From NCERT
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The time period of a simple pendulum in a stationary trolley is \(T_1.\) If the trolley is moving with a constant speed, then time period is \(T_2,\) then: 
1. \(T_1>T _2\)
2. \(T_1<T _2\)
3. \(T_1=T _2\)
4. \(T_2= \infty \)

Subtopic:  Simple Harmonic Motion |
 79%
From NCERT
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A particle executes SHM with a frequency of \(20\) Hz. The frequency with which its potential energy oscillates is:
1. \(5\) Hz
2. \(20\) Hz
3. \(10\) Hz
4. \(40\) Hz

Subtopic:  Energy of SHM |
 73%
From NCERT
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 A particle is moving along the x-axis. The speed of particle v varies with position x as v2144 + x29 = 1. The time period of S.H.M is

1.  π unit

2.  3π2 unit

3.  π2 unit

4.  π4 unit

Subtopic:  Simple Harmonic Motion |
 69%
From NCERT
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