A body has a time period T1 under the action of one force and T2 under the action of another force, the square of the time period when both the forces are acting simultaneously in the same direction is

1. T12T22

2. 2T12T22

3. T12+T22

4. T12T22/(T12+T22)

Subtopic:  Simple Harmonic Motion |
 72%
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Motion of an oscillating liquid column in a U-tube is:

1. periodic but not simple harmonic

2. non-periodic

3. simple harmonic and time period is independent of the density of the liquid

4. simple harmonic and time-period is directly proportional to the density of the liquid

Subtopic:  Simple Harmonic Motion |
 58%
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This time period of a particle undergoing SHM is 16s. It starts motion from the mean position. After 2s, velocity is 0.4 ms-1. The amplitude is:

1. 1.44m

2. 0.72m

3. 2.88m

4. 0.36m

Subtopic:  Simple Harmonic Motion |
 68%
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A particle is performing simple harmonic motion along the x-axis with amplitude 4 cm and time period 1.2 s. The minimum time taken by the particle to move from x=+2 cm to x=+4cm and back again is given by:

1. 0.4 sec

2. 0.3 sec

3. 0.2 sec

4. 0.6 sec

Subtopic:  Simple Harmonic Motion |
 51%
From NCERT
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The acceleration of a particle performing SHM is 12 cm sec-2 at a distance of 3 cm from the mean position. Its time period is:

1. 2.0s

2. 3.14s

3. 0.5s

4. 1.0s

Subtopic:  Simple Harmonic Motion |
 89%
From NCERT
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The acceleration d2x/dt2 of a particle varies with displacement x as d2xdt2=-kx

where k is a constant of the motion. The time period T of the motion is equal to :

1. 2πk

2. 2πk

3. 2π/k

4. 2π/k

Subtopic:  Simple Harmonic Motion |
 87%
From NCERT
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A coin is placed on a horizontal platform, which undergoes horizontal SHM about a mean position O. The coin placed on the platform does not slip, the coefficient of friction between the coin and the platform is μ. The amplitude of oscillation is gradually increased. The coil will begin to slip on the platform for the first time:

1. at the mean position

2. at the extreme position of oscillations

3. for an amplitude of μg/ω2

4. for an amplitude of g/μω2

Subtopic:  Simple Harmonic Motion |
 72%
From NCERT
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A particle moves according to the law, \(x = r \mathrm{cos}\left(\frac{\pi t}{2}\right )\). The distance covered by it in the time interval between \(t=0\) to \(t = 3~\text{s}\) is:
1. \(r\)
2. \(2r\)
3. \(3r\)
4. \(4r\)

Subtopic:  Simple Harmonic Motion |
From NCERT
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A particle is executing SHM of period 24 sec and of amplitude 41 cm with O as equilibrium position. The minimum time in seconds taken by the particle to go from P to Q, where OP=-9cm  and OQ=40cm is:

1. 5

2. 6

3. 7

4. 9

Subtopic:  Simple Harmonic Motion |
 61%
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The figure shows the circular motion of a particle which is at the topmost point on the y-axis at t=0. The radius of the circle is B and the sense of revolution is clockwise.  The time period is indicated in the figure. The simple harmonic motion of the x-projection of the radius vector of the rotating particle P is:
                   

(1) x(t) = Bsin 2πt30

(2) x(t) = Bcos πt15

(3) x(t) = Bsin πt15+π2

(4) x(t) = Bcosπt15+π2

Subtopic:  Phasor Diagram |
 52%
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